3x^2=1250

Solution for 3x^2=1250 equation:

3x^2=1250

We move all terms to the left:

3x^2-(1250)=0

a = 3; b = 0; c = -1250;
Δ = b2-4ac
Δ = 02-4·3·(-1250)
Δ = 15000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15000}=\sqrt{2500*6}=\sqrt{2500}*\sqrt{6}=50\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-50\sqrt{6}}{2*3}=\frac{0-50\sqrt{6}}{6}
=-\frac{50\sqrt{6}}{6}
=-\frac{25\sqrt{6}}{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+50\sqrt{6}}{2*3}=\frac{0+50\sqrt{6}}{6}
=\frac{50\sqrt{6}}{6}
=\frac{25\sqrt{6}}{3}
$